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Binary Search Algorithm-Multiple Choice Question

Question

Consider the following Binary Search Algorithm

upper = length - 1;

lower = 1;

while (upper >= lower)

{ mid_pt = (upper + lower) / 2;

if (data[mid_pt] < target) ; comparison A

{ lower = mid_pt + 1; }

else if (data[mid_pt] == target) ; comparison B

{ return mid_pt; }

else { upper = mid_pt – 1;}

}

//target not found

Give the values for lower, upper and mid-pt for each iteration of the while loop and state how many times will the two comparisons A and B be executed using this algorithm to find the value 77 in the following array? You may not need to complete all the rows.

[0]

[1]

[2]

[3]

[4]

[5]

[6]

[7]

[8]

[9]

[10]

[11]

[12]

14

27

29

38

42

55

57

61

64

69

77

79

84

 

 

 

Lower

Upper

Mid-pt

-

-

-

-

-

-

-

-

-

-

-

-

-

-

-

Comparison A executed ------ times & Comparison B executed ------- times.

 

 

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Comments

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