Change of Angle of Boat Firing Torpedo

Question

A torpedo boat with a displacement of 60 long tons is moving at 18 knots when it fires at 300-lb torpedo horizontally with the launch tube at the 30° angle shown. If the torpedo bas a velocity relative to the boat of 20 ft/sec as it leaves the tube, determine the momentary reduction ∆v in forward speed of the boat. Recall that 1 knot = 1.688 ft/sec and 1 long ton = 2240 lb. Solve the problem also by referring the motion to a coordinate system moving with the initial speed of the boat.

 

Summary

The question belongs to Mechanical Engineering and the question is about calculating the speed of the boat after it launches a torpedo at a 30° angle. The momentary reduction in speed of the boat needs to be calculated. The calculation has been given in the solution in detail.

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